Solve 7x^6>5 - ScanMath

Question

Solve the inequality

Solve the inequality by testing the values in the interval

Solve for x

x \in (- \infty, - \frac{6 84035}{7}) \cup (\frac{6 84035}{7}, + \infty)

Evaluate

7 x^{6} > 5

Move the expression to the left side

7 x^{6} - 5 > 0

Rewrite the expression

7 x^{6} - 5 = 0

Move the constant to the right-hand side and change its sign

7 x^{6} = 0 + 5

Removing 0 doesn't change the value,so remove it from the expression

7 x^{6} = 5

Divide both sides

\frac{7 x ^{6}}{7} = \frac{5}{7}

Divide the numbers

x^{6} = \frac{5}{7}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm 6 \frac{5}{7}

Simplify the expression

More Steps

x = \pm \frac{6 84035}{7}

Separate the equation into 2 possible cases

x = \frac{6 84035}{7} x = - \frac{6 84035}{7}

Determine the test intervals using the critical values

x < - \frac{6 84035}{7} - \frac{6 84035}{7} < x < \frac{6 84035}{7} x > \frac{6 84035}{7}

Choose a value form each interval

x_{1} = - 2 x_{2} = 0 x_{3} = 2

To determine if x < - \frac{6 84035}{7} is the solution to the inequality,test if the chosen value x = - 2 satisfies the initial inequality

More Steps

x < - \frac{6 84035}{7} is the solution x_{2} = 0 x_{3} = 2

To determine if - \frac{6 84035}{7} < x < \frac{6 84035}{7} is the solution to the inequality,test if the chosen value x = 0 satisfies the initial inequality

More Steps

x < - \frac{6 84035}{7} is the solution - \frac{6 84035}{7} < x < \frac{6 84035}{7} is not a solution x_{3} = 2

To determine if x > \frac{6 84035}{7} is the solution to the inequality,test if the chosen value x = 2 satisfies the initial inequality

More Steps

x < - \frac{6 84035}{7} is the solution - \frac{6 84035}{7} < x < \frac{6 84035}{7} is not a solution x > \frac{6 84035}{7} is the solution

Solution

x \in (- \infty, - \frac{6 84035}{7}) \cup (\frac{6 84035}{7}, + \infty)

Show Solution