Solve 8 -k^2(4-2k)=k^2k

Question

Solve the equation

k_{1} = 1 - 5, k_{2} = 2, k_{3} = 1 + 5

Alternative Form

k_{1} \approx - 1.236068, k_{2} = 2, k_{3} \approx 3.236068

Evaluate

8 - k^{2} (4 - 2 k) = k^{2} \times k

Multiply the terms

More Steps

8 - k^{2} (4 - 2 k) = k^{3}

Move the expression to the left side

8 - k^{2} (4 - 2 k) - k^{3} = 0

Calculate

More Steps

8 - 4 k^{2} + k^{3} = 0

Factor the expression

(2 - k) (4 + 2 k - k^{2}) = 0

Separate the equation into 2 possible cases

2 - k = 0 4 + 2 k - k^{2} = 0

Solve the equation

More Steps

k = 2 4 + 2 k - k^{2} = 0

Solve the equation

More Steps

k = 2 k = 1 + 5 k = 1 - 5

Solution

k_{1} = 1 - 5, k_{2} = 2, k_{3} = 1 + 5

Alternative Form

k_{1} \approx - 1.236068, k_{2} = 2, k_{3} \approx 3.236068

Show Solution