Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
k1=−1,k2=1
Evaluate
8−12k5=−4
Move the expression to the left side
8−12k5−(−4)=0
Subtract the numbers
More Steps
Evaluate
8−(−4)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
8+4
Add the numbers
12
12−12k5=0
Separate the equation into 2 possible cases
12−12k5=0,k5≥012−12(−k5)=0,k5<0
Solve the equation
More Steps
Evaluate
12−12k5=0
Move the constant to the right-hand side and change its sign
−12k5=0−12
Removing 0 doesn't change the value,so remove it from the expression
−12k5=−12
Change the signs on both sides of the equation
12k5=12
Divide both sides
1212k5=1212
Divide the numbers
k5=1212
Divide the numbers
More Steps
Evaluate
1212
Reduce the numbers
11
Calculate
1
k5=1
Take the 5-th root on both sides of the equation
5k5=51
Calculate
k=51
Simplify the root
k=1
k=1,k5≥012−12(−k5)=0,k5<0
The only way a base raised to an odd power can be greater than or equal to 0 is if the base is greater than or equal to 0
k=1,k≥012−12(−k5)=0,k5<0
Solve the equation
More Steps
Evaluate
12−12(−k5)=0
Calculate
12+12k5=0
Move the constant to the right-hand side and change its sign
12k5=0−12
Removing 0 doesn't change the value,so remove it from the expression
12k5=−12
Divide both sides
1212k5=12−12
Divide the numbers
k5=12−12
Divide the numbers
More Steps
Evaluate
12−12
Reduce the numbers
1−1
Calculate
−1
k5=−1
Take the 5-th root on both sides of the equation
5k5=5−1
Calculate
k=5−1
Simplify the root
More Steps
Evaluate
5−1
An odd root of a negative radicand is always a negative
−51
Simplify the radical expression
−1
k=−1
k=1,k≥0k=−1,k5<0
The only way a base raised to an odd power can be less than 0 is if the base is less than 0
k=1,k≥0k=−1,k<0
Find the intersection
k=1k=−1,k<0
Find the intersection
k=1k=−1
Solution
k1=−1,k2=1
Show Solution
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