Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
k1=−1,k2=0,k3=1
Evaluate
8k3−2k=3(2k×1)
Remove the parentheses
8k3−2k=3×2k×1
Multiply the terms
More Steps
Evaluate
3×2k×1
Rewrite the expression
3×2k
Multiply the terms
6k
8k3−2k=6k
Move the expression to the left side
8k3−2k−6k=0
Subtract the terms
More Steps
Evaluate
−2k−6k
Collect like terms by calculating the sum or difference of their coefficients
(−2−6)k
Subtract the numbers
−8k
8k3−8k=0
Factor the expression
8k(k2−1)=0
Divide both sides
k(k2−1)=0
Separate the equation into 2 possible cases
k=0k2−1=0
Solve the equation
More Steps
Evaluate
k2−1=0
Move the constant to the right-hand side and change its sign
k2=0+1
Removing 0 doesn't change the value,so remove it from the expression
k2=1
Take the root of both sides of the equation and remember to use both positive and negative roots
k=±1
Simplify the expression
k=±1
Separate the equation into 2 possible cases
k=1k=−1
k=0k=1k=−1
Solution
k1=−1,k2=0,k3=1
Show Solution
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