Solve 8t^2-128 - ScanMath

Evaluate

8 t^{2} - 128

To find the roots of the expression,set the expression equal to 0

8 t^{2} - 128 = 0

Move the constant to the right-hand side and change its sign

8 t^{2} = 0 + 128

Removing 0 doesn't change the value,so remove it from the expression

8 t^{2} = 128

Divide both sides

\frac{8 t ^{2}}{8} = \frac{128}{8}

Divide the numbers

t^{2} = \frac{128}{8}

Divide the numbers

More Steps

t^{2} = 16

Take the root of both sides of the equation and remember to use both positive and negative roots

t = \pm 16

Simplify the expression

More Steps

t = \pm 4

Separate the equation into 2 possible cases

t = 4 t = - 4

Solution

t_{1} = - 4, t_{2} = 4

Factor the expression