Solve 8x^2<=8x-9 - ScanMath

Evaluate

8 x^{2} \leq 8 x - 9

Move the expression to the left side

8 x^{2} - (8 x - 9) \leq 0

If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses

8 x^{2} - 8 x + 9 \leq 0

Rewrite the expression

8 x^{2} - 8 x + 9 = 0

Add or subtract both sides

8 x^{2} - 8 x = - 9

Divide both sides

\frac{8 x ^{2} - 8 x}{8} = \frac{- 9}{8}

Evaluate

x^{2} - x = - \frac{9}{8}

Add the same value to both sides

x^{2} - x + \frac{1}{4} = - \frac{9}{8} + \frac{1}{4}

Simplify the expression

(x - \frac{1}{2})^{2} = - \frac{7}{8}

Since the left-hand side is always positive or 0,and the right-hand side is always negative,the statement is false for any value of x

x \in / R

There are no key numbers,so choose any value to test,for example x = 0

x = 0

Solution

More Steps

x \in \emptyset

Alternative Form

No solution

Solve the inequality