Solve 8x^2-3x-2=0

Evaluate

8 x^{2} - 3 x - 2 = 0

Substitute a= 8,b= - 3 and c= - 2 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 8 ( - 2 )}{2 \times 8}

Simplify the expression

x = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 8 ( - 2 )}{16}

Simplify the expression

More Steps

x = \frac{3 \pm 73}{16}

Separate the equation into 2 possible cases

x = \frac{3 + 73}{16} x = \frac{3 - 73}{16}

Solution

x_{1} = \frac{3 - 73}{16}, x_{2} = \frac{3 + 73}{16}

Alternative Form

x_{1} \approx - 0.3465, x_{2} \approx 0.7215

Solve the quadratic equation