Question Solve the quadratic equation Solve by factoring Solve using the quadratic formula Solve by completing the square Load more y1=−21,y2=1Alternative Form y1=−0.5,y2=1 Evaluate 8y2−4y−4=0Factor the expression More Steps Evaluate 8y2−4y−4Rewrite the expression 4×2y2−4y−4Factor out 4 from the expression 4(2y2−y−1)Factor the expression More Steps Evaluate 2y2−y−1Rewrite the expression 2y2+(1−2)y−1Calculate 2y2+y−2y−1Rewrite the expression y×2y+y−2y−1Factor out y from the expression y(2y+1)−2y−1Factor out −1 from the expression y(2y+1)−(2y+1)Factor out 2y+1 from the expression (y−1)(2y+1) 4(y−1)(2y+1) 4(y−1)(2y+1)=0Divide the terms (y−1)(2y+1)=0When the product of factors equals 0,at least one factor is 0 y−1=02y+1=0Solve the equation for y More Steps Evaluate y−1=0Move the constant to the right-hand side and change its sign y=0+1Removing 0 doesn't change the value,so remove it from the expression y=1 y=12y+1=0Solve the equation for y More Steps Evaluate 2y+1=0Move the constant to the right-hand side and change its sign 2y=0−1Removing 0 doesn't change the value,so remove it from the expression 2y=−1Divide both sides 22y=2−1Divide the numbers y=2−1Use b−a=−ba=−ba to rewrite the fraction y=−21 y=1y=−21Solution y1=−21,y2=1Alternative Form y1=−0.5,y2=1 Show Solution Graph