Solve 9x 7 = 5x^31

Question

Solve the equation

x_{1} = - \frac{3 35}{5}, x_{2} = 0, x_{3} = \frac{3 35}{5}

Alternative Form

x_{1} \approx - 3.549648, x_{2} = 0, x_{3} \approx 3.549648

Evaluate

9 x \times 7 = 5 x^{3} \times 1

Multiply the terms

63 x = 5 x^{3} \times 1

Multiply the terms

63 x = 5 x^{3}

Add or subtract both sides

63 x - 5 x^{3} = 0

Factor the expression

x (63 - 5 x^{2}) = 0

Separate the equation into 2 possible cases

x = 0 63 - 5 x^{2} = 0

Solve the equation

More Steps

Evaluate

63 - 5 x^{2} = 0

Move the constant to the right-hand side and change its sign

- 5 x^{2} = 0 - 63

Removing 0 doesn't change the value,so remove it from the expression

- 5 x^{2} = - 63

Change the signs on both sides of the equation

5 x^{2} = 63

Divide both sides

\frac{5 x ^{2}}{5} = \frac{63}{5}

Divide the numbers

x^{2} = \frac{63}{5}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm \frac{63}{5}

Simplify the expression

More Steps

Evaluate

\frac{63}{5}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{63}{5}

Simplify the radical expression

\frac{3 7}{5}

Multiply by the Conjugate

\frac{3 7 \times 5}{5 \times 5}

Multiply the numbers

\frac{3 35}{5 \times 5}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{3 35}{5}

x = \pm \frac{3 35}{5}

Separate the equation into 2 possible cases

x = \frac{3 35}{5} x = - \frac{3 35}{5}

x = 0 x = \frac{3 35}{5} x = - \frac{3 35}{5}

Solution

x_{1} = - \frac{3 35}{5}, x_{2} = 0, x_{3} = \frac{3 35}{5}

Alternative Form

x_{1} \approx - 3.549648, x_{2} = 0, x_{3} \approx 3.549648

Show Solution