Solve 9x^2-32x-8 - ScanMath

Question

Find the roots

x_{1} = \frac{16 - 2 82}{9}, x_{2} = \frac{16 + 2 82}{9}

Alternative Form

x_{1} \approx - 0.23453, x_{2} \approx 3.790086

Evaluate

9 x^{2} - 32 x - 8

To find the roots of the expression,set the expression equal to 0

9 x^{2} - 32 x - 8 = 0

Substitute a= 9,b= - 32 and c= - 8 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{32 \pm ( - 32 ) ^{2} - 4 \times 9 ( - 8 )}{2 \times 9}

Simplify the expression

x = \frac{32 \pm ( - 32 ) ^{2} - 4 \times 9 ( - 8 )}{18}

Simplify the expression

More Steps

x = \frac{32 \pm 1312}{18}

Simplify the radical expression

More Steps

x = \frac{32 \pm 4 82}{18}

Separate the equation into 2 possible cases

x = \frac{32 + 4 82}{18} x = \frac{32 - 4 82}{18}

Simplify the expression

More Steps

x = \frac{16 + 2 82}{9} x = \frac{32 - 4 82}{18}

Simplify the expression

More Steps

x = \frac{16 + 2 82}{9} x = \frac{16 - 2 82}{9}

Solution

x_{1} = \frac{16 - 2 82}{9}, x_{2} = \frac{16 + 2 82}{9}

Alternative Form

x_{1} \approx - 0.23453, x_{2} \approx 3.790086

Show Solution