Solve B^588-12B - ScanMath

Question

Simplify the expression

88 B^{5} - 12 B

Evaluate

B^{5} \times 88 - 12 B

Solution

88 B^{5} - 12 B

Show Solution

4 B (22 B^{4} - 3)

Evaluate

B^{5} \times 88 - 12 B

Use the commutative property to reorder the terms

88 B^{5} - 12 B

Rewrite the expression

4 B \times 22 B^{4} - 4 B \times 3

Solution

4 B (22 B^{4} - 3)

Show Solution

B_{1} = - \frac{4 31944}{22}, B_{2} = 0, B_{3} = \frac{4 31944}{22}

Alternative Form

B_{1} \approx - 0.60768, B_{2} = 0, B_{3} \approx 0.60768

Evaluate

B^{5} \times 88 - 12 B

To find the roots of the expression,set the expression equal to 0

B^{5} \times 88 - 12 B = 0

Use the commutative property to reorder the terms

88 B^{5} - 12 B = 0

Factor the expression

4 B (22 B^{4} - 3) = 0

Divide both sides

B (22 B^{4} - 3) = 0

Separate the equation into 2 possible cases

B = 0 22 B^{4} - 3 = 0

Solve the equation

More Steps

Evaluate

22 B^{4} - 3 = 0

Move the constant to the right-hand side and change its sign

22 B^{4} = 0 + 3

Removing 0 doesn't change the value,so remove it from the expression

22 B^{4} = 3

Divide both sides

\frac{22 B ^{4}}{22} = \frac{3}{22}

Divide the numbers

B^{4} = \frac{3}{22}

Take the root of both sides of the equation and remember to use both positive and negative roots

B = \pm 4 \frac{3}{22}

Simplify the expression

More Steps

Evaluate

4 \frac{3}{22}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 3}{4 22}

Multiply by the Conjugate

\frac{4 3 \times 4 2 2 ^{3}}{4 22 \times 4 2 2 ^{3}}

Simplify

\frac{4 3 \times 4 10648}{4 22 \times 4 2 2 ^{3}}

Multiply the numbers

\frac{4 31944}{4 22 \times 4 2 2 ^{3}}

Multiply the numbers

\frac{4 31944}{22}

B = \pm \frac{4 31944}{22}

Separate the equation into 2 possible cases

B = \frac{4 31944}{22} B = - \frac{4 31944}{22}

B = 0 B = \frac{4 31944}{22} B = - \frac{4 31944}{22}

Solution

B_{1} = - \frac{4 31944}{22}, B_{2} = 0, B_{3} = \frac{4 31944}{22}

Alternative Form

B_{1} \approx - 0.60768, B_{2} = 0, B_{3} \approx 0.60768

Show Solution