Solve K^5048-1 - ScanMath

Evaluate

K^{5} \times 48 - 1

To find the roots of the expression,set the expression equal to 0

K^{5} \times 48 - 1 = 0

Use the commutative property to reorder the terms

48 K^{5} - 1 = 0

Move the constant to the right-hand side and change its sign

48 K^{5} = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

48 K^{5} = 1

Divide both sides

\frac{48 K ^{5}}{48} = \frac{1}{48}

Divide the numbers

K^{5} = \frac{1}{48}

Take the 5 -th root on both sides of the equation

5 K^{5} = 5 \frac{1}{48}

Calculate

K = 5 \frac{1}{48}

Solution

More Steps

K = \frac{5 4 8 ^{4}}{48}

Alternative Form

K \approx 0.461054

Simplify the expression