Solve M^35-M - ScanMath

Question

Simplify the expression

5 M^{3} - M

Evaluate

M^{3} \times 5 - M

Solution

5 M^{3} - M

Show Solution

M (5 M^{2} - 1)

Evaluate

M^{3} \times 5 - M

Use the commutative property to reorder the terms

5 M^{3} - M

Rewrite the expression

M \times 5 M^{2} - M

Solution

M (5 M^{2} - 1)

Show Solution

M_{1} = - \frac{5}{5}, M_{2} = 0, M_{3} = \frac{5}{5}

Alternative Form

M_{1} \approx - 0.447214, M_{2} = 0, M_{3} \approx 0.447214

Evaluate

M^{3} \times 5 - M

To find the roots of the expression,set the expression equal to 0

M^{3} \times 5 - M = 0

Use the commutative property to reorder the terms

5 M^{3} - M = 0

Factor the expression

M (5 M^{2} - 1) = 0

Separate the equation into 2 possible cases

M = 0 5 M^{2} - 1 = 0

Solve the equation

More Steps

Evaluate

5 M^{2} - 1 = 0

Move the constant to the right-hand side and change its sign

5 M^{2} = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

5 M^{2} = 1

Divide both sides

\frac{5 M ^{2}}{5} = \frac{1}{5}

Divide the numbers

M^{2} = \frac{1}{5}

Take the root of both sides of the equation and remember to use both positive and negative roots

M = \pm \frac{1}{5}

Simplify the expression

More Steps

Evaluate

\frac{1}{5}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{1}{5}

Simplify the radical expression

\frac{1}{5}

Multiply by the Conjugate

\frac{5}{5 \times 5}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{5}{5}

M = \pm \frac{5}{5}

Separate the equation into 2 possible cases

M = \frac{5}{5} M = - \frac{5}{5}

M = 0 M = \frac{5}{5} M = - \frac{5}{5}

Solution

M_{1} = - \frac{5}{5}, M_{2} = 0, M_{3} = \frac{5}{5}

Alternative Form

M_{1} \approx - 0.447214, M_{2} = 0, M_{3} \approx 0.447214

Show Solution