Question
Function
Find the first partial derivative with respect to c
Find the first partial derivative with respect to v
∂c∂Q=v1
Simplify
Q=vc
Find the first partial derivative by treating the variable v as a constant and differentiating with respect to c
∂c∂Q=∂c∂(vc)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂c∂Q=v2∂c∂(c)v−c×∂c∂(v)
Use ∂x∂xn=nxn−1 to find derivative
∂c∂Q=v21×v−c×∂c∂(v)
Use ∂x∂(c)=0 to find derivative
∂c∂Q=v21×v−c×0
Any expression multiplied by 1 remains the same
∂c∂Q=v2v−c×0
Any expression multiplied by 0 equals 0
∂c∂Q=v2v−0
Removing 0 doesn't change the value,so remove it from the expression
∂c∂Q=v2v
Solution
More Steps

Evaluate
v2v
Use the product rule aman=an−m to simplify the expression
v2−11
Reduce the fraction
v1
∂c∂Q=v1
Show Solution

Solve the equation
Solve for c
Solve for v
c=Qv
Evaluate
Q=vc
Swap the sides of the equation
vc=Q
Cross multiply
c=vQ
Solution
c=Qv
Show Solution
