Question
Function
Find the first partial derivative with respect to b
Find the first partial derivative with respect to c
∂b∂a=2cb
Evaluate
1a=4b×cb−34
Divide the terms
a=4b×cb−34
Multiply the terms
More Steps

Multiply the terms
4b×cb
Multiply the terms
4cb×b
Multiply the terms
4cb2
a=4cb2−34
Find the first partial derivative by treating the variable c as a constant and differentiating with respect to b
∂b∂a=∂b∂(4cb2−34)
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂b∂a=∂b∂(4cb2)−∂b∂(34)
Evaluate
More Steps

Evaluate
∂b∂(4cb2)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
(4c)2∂b∂(b2)×4c−b2×∂b∂(4c)
Use ∂x∂xn=nxn−1 to find derivative
(4c)22b×4c−b2×∂b∂(4c)
Use ∂x∂(c)=0 to find derivative
(4c)22b×4c−b2×0
Multiply the numbers
(4c)28bc−b2×0
Any expression multiplied by 0 equals 0
(4c)28bc−0
Evaluate
16c28bc−0
Removing 0 doesn't change the value,so remove it from the expression
16c28bc
Use the product rule aman=an−m to simplify the expression
16c2−18b
Reduce the fraction
16c8b
Cancel out the common factor 8
2cb
∂b∂a=2cb−∂b∂(34)
Evaluate
∂b∂a=2cb−0
Solution
∂b∂a=2cb
Show Solution

Solve the equation
Solve for a
Solve for b
Solve for c
a=12c3b2−16c
Evaluate
1a=4b×cb−34
Divide the terms
a=4b×cb−34
Multiply the terms
More Steps

Multiply the terms
4b×cb
Multiply the terms
4cb×b
Multiply the terms
4cb2
a=4cb2−34
Solution
a=12c3b2−16c
Show Solution
