Question
Function
Find the first partial derivative with respect to h
Find the first partial derivative with respect to b
∂h∂a=21b+21b2
Evaluate
a=21h(b×1+b2)
Any expression multiplied by 1 remains the same
a=21h(b+b2)
Find the first partial derivative by treating the variable b as a constant and differentiating with respect to h
∂h∂a=∂h∂(21h(b+b2))
Rewrite the expression
∂h∂a=∂h∂(2h(b+b2))
Use differentiation rules
∂h∂a=21×∂h∂(h(b+b2))
Calculate the derivative
More Steps

Evaluate
∂h∂(h(b+b2))
Use differentiation rule ∂x∂(f(x)×g(x))=∂x∂(f(x))×g(x)+f(x)×∂x∂(g(x))
∂h∂(h)(b+b2)+h×∂h∂(b+b2)
Use ∂x∂xn=nxn−1 to find derivative
1×(b+b2)+h×∂h∂(b+b2)
Evaluate
b+b2+h×∂h∂(b+b2)
Use ∂x∂(c)=0 to find derivative
b+b2+h×0
Evaluate
b+b2+0
Removing 0 doesn't change the value,so remove it from the expression
b+b2
∂h∂a=21(b+b2)
Solution
∂h∂a=21b+21b2
Show Solution

Solve the equation
Solve for a
Solve for b
Solve for h
a=2bh+b2h
Evaluate
a=21h(b×1+b2)
Any expression multiplied by 1 remains the same
a=21h(b+b2)
Solution
a=2bh+b2h
Show Solution
