Question
Function
Find the first partial derivative with respect to s
Find the first partial derivative with respect to t
∂s∂a=t22
Evaluate
a=2×t2s
Multiply the terms
a=t22s
Find the first partial derivative by treating the variable t as a constant and differentiating with respect to s
∂s∂a=∂s∂(t22s)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂s∂a=(t2)2∂s∂(2s)t2−2s×∂s∂(t2)
Evaluate
More Steps

Evaluate
∂s∂(2s)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
2×∂s∂(s)
Use ∂x∂xn=nxn−1 to find derivative
2×1
Multiply the terms
2
∂s∂a=(t2)22t2−2s×∂s∂(t2)
Use ∂x∂(c)=0 to find derivative
∂s∂a=(t2)22t2−2s×0
Any expression multiplied by 0 equals 0
∂s∂a=(t2)22t2−0
Evaluate
More Steps

Evaluate
(t2)2
Multiply the exponents
t2×2
Multiply the terms
t4
∂s∂a=t42t2−0
Removing 0 doesn't change the value,so remove it from the expression
∂s∂a=t42t2
Solution
More Steps

Evaluate
t42t2
Use the product rule aman=an−m to simplify the expression
t4−22
Reduce the fraction
t22
∂s∂a=t22
Show Solution

Solve the equation
Solve for a
Solve for s
Solve for t
a=t22s
Evaluate
a=2×t2s
Solution
a=t22s
Show Solution
