Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
a=−5
Evaluate
a2−a3=150
Move the expression to the left side
a2−a3−150=0
Factor the expression
(a+5)(6a−a2−30)=0
Separate the equation into 2 possible cases
a+5=06a−a2−30=0
Solve the equation
More Steps
Evaluate
a+5=0
Move the constant to the right-hand side and change its sign
a=0−5
Removing 0 doesn't change the value,so remove it from the expression
a=−5
a=−56a−a2−30=0
Solve the equation
More Steps
Evaluate
6a−a2−30=0
Rewrite in standard form
−a2+6a−30=0
Multiply both sides
a2−6a+30=0
Substitute a=1,b=−6 and c=30 into the quadratic formula a=2a−b±b2−4ac
a=26±(−6)2−4×30
Simplify the expression
More Steps
Evaluate
(−6)2−4×30
Multiply the numbers
(−6)2−120
Rewrite the expression
62−120
Evaluate the power
36−120
Subtract the numbers
−84
a=26±−84
The expression is undefined in the set of real numbers
a∈/R
a=−5a∈/R
Solution
a=−5
Show Solution
Graph
