Solve b=200 x ; b x=230 - ScanMath

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Question

Solve the system of equations

(b_{1}, x_{1}) = (- 20115, - \frac{115}{10}) (b_{2}, x_{2}) = (20115, \frac{115}{10})

Evaluate

{b = 200 x b x = 230

Substitute the given value of b into the equation b x = 230

200 x \times x = 230

Simplify

200 x^{2} = 230

Divide both sides

\frac{200 x ^{2}}{200} = \frac{230}{200}

Divide the numbers

x^{2} = \frac{230}{200}

Cancel out the common factor 10

x^{2} = \frac{23}{20}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm \frac{23}{20}

Simplify the expression

More Steps

x = \pm \frac{115}{10}

Separate the equation into 2 possible cases

x = \frac{115}{10} \cup x = - \frac{115}{10}

Rearrange the terms

{b = 200 x x = \frac{115}{10} \cup {b = 200 x x = - \frac{115}{10}

Calculate

More Steps

{b = 20115 x = \frac{115}{10} \cup {b = 200 x x = - \frac{115}{10}

Calculate

More Steps

{b = 20115 x = \frac{115}{10} \cup {b = - 20115 x = - \frac{115}{10}

Calculate

{b = - 20115 x = - \frac{115}{10} \cup {b = 20115 x = \frac{115}{10}

Check the solution

More Steps

{b = - 20115 x = - \frac{115}{10} \cup {b = 20115 x = \frac{115}{10}

Check the solution

More Steps

{b = - 20115 x = - \frac{115}{10} \cup {b = 20115 x = \frac{115}{10}

Solution

(b_{1}, x_{1}) = (- 20115, - \frac{115}{10}) (b_{2}, x_{2}) = (20115, \frac{115}{10})

Show Solution