Solve b^3 (a-5)i=a 8

Evaluate

b^{3} (a - 5) i = a \times 8

Use the commutative property to reorder the terms

i b^{3} (a - 5) = a \times 8

Use the commutative property to reorder the terms

i b^{3} (a - 5) = 8 a

Expand the expression

More Steps

i b^{3} a - 5 i b^{3} = 8 a

Move the expression to the left side

i b^{3} a - 5 i b^{3} - 8 a = 0

Rewrite the expression

- 8 a + (b^{3} a - 5 b^{3}) i = 0

Rewrite the expression

{- 8 a = 0 b^{3} a - 5 b^{3} = 0

Solve the equation for a

More Steps

{a = 0 b^{3} a - 5 b^{3} = 0

Substitute the given value of a into the equation b^{3} a - 5 b^{3} = 0

b^{3} \times 0 - 5 b^{3} = 0

Simplify

More Steps

- 5 b^{3} = 0

Change the signs on both sides of the equation

5 b^{3} = 0

Rewrite the expression

b^{3} = 0

The only way a power can be 0 is when the base equals 0

b = 0

Calculate

{a = 0 b = 0

Solution

(a, b) = (0, 0)