Solve b12-b9-b^6 - ScanMath

Question

Simplify the expression

3 b - b^{6}

Evaluate

b \times 12 - b \times 9 - b^{6}

Use the commutative property to reorder the terms

12 b - b \times 9 - b^{6}

Use the commutative property to reorder the terms

12 b - 9 b - b^{6}

Solution

More Steps

Evaluate

12 b - 9 b

Collect like terms by calculating the sum or difference of their coefficients

(12 - 9) b

Subtract the numbers

3 b

3 b - b^{6}

Show Solution

b (3 - b^{5})

Evaluate

b \times 12 - b \times 9 - b^{6}

Use the commutative property to reorder the terms

12 b - b \times 9 - b^{6}

Use the commutative property to reorder the terms

12 b - 9 b - b^{6}

Subtract the terms

More Steps

Simplify

12 b - 9 b

Collect like terms by calculating the sum or difference of their coefficients

(12 - 9) b

Subtract the numbers

3 b

3 b - b^{6}

Rewrite the expression

b \times 3 - b \times b^{5}

Solution

b (3 - b^{5})

Show Solution

b_{1} = 0, b_{2} = 53

Alternative Form

b_{1} = 0, b_{2} \approx 1.245731

Evaluate

b \times 12 - b \times 9 - b^{6}

To find the roots of the expression,set the expression equal to 0

b \times 12 - b \times 9 - b^{6} = 0

Use the commutative property to reorder the terms

12 b - b \times 9 - b^{6} = 0

Use the commutative property to reorder the terms

12 b - 9 b - b^{6} = 0

Subtract the terms

More Steps

Simplify

12 b - 9 b

Collect like terms by calculating the sum or difference of their coefficients

(12 - 9) b

Subtract the numbers

3 b

3 b - b^{6} = 0

Factor the expression

b (3 - b^{5}) = 0

Separate the equation into 2 possible cases

b = 0 3 - b^{5} = 0

Solve the equation

More Steps

Evaluate

3 - b^{5} = 0

Move the constant to the right-hand side and change its sign

- b^{5} = 0 - 3

Removing 0 doesn't change the value,so remove it from the expression

- b^{5} = - 3

Change the signs on both sides of the equation

b^{5} = 3

Take the 5 -th root on both sides of the equation

5 b^{5} = 53

Calculate

b = 53

b = 0 b = 53

Solution

b_{1} = 0, b_{2} = 53

Alternative Form

b_{1} = 0, b_{2} \approx 1.245731

Show Solution