Question
Solve the system of equations
Solve using the substitution method
Solve using the elimination method
(c1,h1)=(0,0)(c2,h2)=(1,2)
Evaluate
{c=2hc2hc=2h
Calculate
{c=2hc2hc=2h
Calculate
{c=2hc2hc=2h
Solve the equation
More Steps

Evaluate
c=2hc
Cross multiply
c×2=hc
Simplify the equation
2c=hc
Move the expression to the left side
2c−hc=0
Factor the expression
c(2−h)=0
Separate the equation into 2 possible cases
c=0∪2−h=0
Solve the equation
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Evaluate
2−h=0
Move the constant to the right-hand side and change its sign
−h=0−2
Removing 0 doesn't change the value,so remove it from the expression
−h=−2
Change the signs on both sides of the equation
h=2
c=0∪h=2
{c=0∪h=22hc=2h
Evaluate
{c=02hc=2h∪{h=22hc=2h
Calculate
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Evaluate
{c=02hc=2h
Substitute the given value of c into the equation 2hc=2h
2h×0=2h
Simplify
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Evaluate
2h×0
Any expression multiplied by 0 equals 0
20
Divide the terms
0
0=2h
Swap the sides of the equation
2h=0
Simplify
h=0
Calculate
{c=0h=0
{c=0h=0∪{h=22hc=2h
Calculate
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Evaluate
{h=22hc=2h
Substitute the given value of h into the equation 2hc=2h
22c=22
Simplify
c=22
Simplify
c=1
Calculate
{c=1h=2
{c=0h=0∪{c=1h=2
Check the solution
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Check the solution
{0=20×020×0=20
Simplify
{0=00=0
Evaluate
true
{c=0h=0∪{c=1h=2
Check the solution
More Steps

Check the solution
{1=22×122×1=22
Simplify
{1=11=1
Evaluate
true
{c=0h=0∪{c=1h=2
Solution
(c1,h1)=(0,0)(c2,h2)=(1,2)
Show Solution
