Solve c^5402-15-2

Question

Simplify the expression

402 c^{5} - 17

Evaluate

c^{5} \times 402 - 15 - 2

Use the commutative property to reorder the terms

402 c^{5} - 15 - 2

Solution

402 c^{5} - 17

Show Solution

c = \frac{5 17 \times 40 2 ^{4}}{402}

Alternative Form

c \approx 0.531183

Evaluate

c^{5} \times 402 - 15 - 2

To find the roots of the expression,set the expression equal to 0

c^{5} \times 402 - 15 - 2 = 0

Use the commutative property to reorder the terms

402 c^{5} - 15 - 2 = 0

Subtract the numbers

402 c^{5} - 17 = 0

Move the constant to the right-hand side and change its sign

402 c^{5} = 0 + 17

Removing 0 doesn't change the value,so remove it from the expression

402 c^{5} = 17

Divide both sides

\frac{402 c ^{5}}{402} = \frac{17}{402}

Divide the numbers

c^{5} = \frac{17}{402}

Take the 5 -th root on both sides of the equation

5 c^{5} = 5 \frac{17}{402}

Calculate

c = 5 \frac{17}{402}

Solution

More Steps

Evaluate

5 \frac{17}{402}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{5 17}{5 402}

Multiply by the Conjugate

\frac{5 17 \times 5 40 2 ^{4}}{5 402 \times 5 40 2 ^{4}}

The product of roots with the same index is equal to the root of the product

\frac{5 17 \times 40 2 ^{4}}{5 402 \times 5 40 2 ^{4}}

Multiply the numbers

More Steps

Evaluate

5402 \times 5 40 2^{4}

The product of roots with the same index is equal to the root of the product

5 402 \times 40 2^{4}

Calculate the product

5 40 2^{5}

Reduce the index of the radical and exponent with 5

402

\frac{5 17 \times 40 2 ^{4}}{402}

c = \frac{5 17 \times 40 2 ^{4}}{402}

Alternative Form

c \approx 0.531183

Show Solution