Solve c^550112-22-9

Question

Simplify the expression

50112 c^{5} - 31

Evaluate

c^{5} \times 50112 - 22 - 9

Use the commutative property to reorder the terms

50112 c^{5} - 22 - 9

Solution

50112 c^{5} - 31

Show Solution

c = \frac{5 31 \times 156 6 ^{4}}{3132}

Alternative Form

c \approx 0.228183

Evaluate

c^{5} \times 50112 - 22 - 9

To find the roots of the expression,set the expression equal to 0

c^{5} \times 50112 - 22 - 9 = 0

Use the commutative property to reorder the terms

50112 c^{5} - 22 - 9 = 0

Subtract the numbers

50112 c^{5} - 31 = 0

Move the constant to the right-hand side and change its sign

50112 c^{5} = 0 + 31

Removing 0 doesn't change the value,so remove it from the expression

50112 c^{5} = 31

Divide both sides

\frac{50112 c ^{5}}{50112} = \frac{31}{50112}

Divide the numbers

c^{5} = \frac{31}{50112}

Take the 5 -th root on both sides of the equation

5 c^{5} = 5 \frac{31}{50112}

Calculate

c = 5 \frac{31}{50112}

Solution

More Steps

Evaluate

5 \frac{31}{50112}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{5 31}{5 50112}

Simplify the radical expression

More Steps

Evaluate

550112

Write the expression as a product where the root of one of the factors can be evaluated

5 32 \times 1566

Write the number in exponential form with the base of 2

5 2^{5} \times 1566

The root of a product is equal to the product of the roots of each factor

5 2^{5} \times 51566

Reduce the index of the radical and exponent with 5

251566

\frac{5 31}{2 5 1566}

Multiply by the Conjugate

\frac{5 31 \times 5 156 6 ^{4}}{2 5 1566 \times 5 156 6 ^{4}}

The product of roots with the same index is equal to the root of the product

\frac{5 31 \times 156 6 ^{4}}{2 5 1566 \times 5 156 6 ^{4}}

Multiply the numbers

More Steps

Evaluate

251566 \times 5 156 6^{4}

Multiply the terms

2 \times 1566

Multiply the terms

3132

\frac{5 31 \times 156 6 ^{4}}{3132}

c = \frac{5 31 \times 156 6 ^{4}}{3132}

Alternative Form

c \approx 0.228183

Show Solution