Question
Factor the expression
(c−1)(c2+c+1)(c+1)(c2−c+1)
Evaluate
c6−1
Rewrite the expression in exponential form
(c3)2−12
Use a2−b2=(a−b)(a+b) to factor the expression
(c3−1)(c3+1)
Evaluate
More Steps

Evaluate
c3−1
Rewrite the expression in exponential form
c3−13
Use a3−b3=(a−b)(a2+ab+b2) to factor the expression
(c−1)(c2+c×1+12)
Any expression multiplied by 1 remains the same
(c−1)(c2+c+12)
1 raised to any power equals to 1
(c−1)(c2+c+1)
(c−1)(c2+c+1)(c3+1)
Solution
More Steps

Evaluate
c3+1
Rewrite the expression in exponential form
c3+13
Use a3+b3=(a+b)(a2−ab+b2) to factor the expression
(c+1)(c2−c×1+12)
Any expression multiplied by 1 remains the same
(c+1)(c2−c+12)
1 raised to any power equals to 1
(c+1)(c2−c+1)
(c−1)(c2+c+1)(c+1)(c2−c+1)
Show Solution

Find the roots
c1=−1,c2=1
Evaluate
c6−1
To find the roots of the expression,set the expression equal to 0
c6−1=0
Move the constant to the right-hand side and change its sign
c6=0+1
Removing 0 doesn't change the value,so remove it from the expression
c6=1
Take the root of both sides of the equation and remember to use both positive and negative roots
c=±61
Simplify the expression
c=±1
Separate the equation into 2 possible cases
c=1c=−1
Solution
c1=−1,c2=1
Show Solution
