Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
χ2fc−χ2f−χ2c+χ2
Evaluate
χ2((f−1)(c−1))
Remove the parentheses
χ2(f−1)(c−1)
Multiply the terms
More Steps
Evaluate
χ2(f−1)
Apply the distributive property
χ2f−χ2×1
Any expression multiplied by 1 remains the same
χ2f−χ2
(χ2f−χ2)(c−1)
Apply the distributive property
χ2fc−χ2f×1−χ2c−(−χ2×1)
Any expression multiplied by 1 remains the same
χ2fc−χ2f−χ2c−(−χ2×1)
Any expression multiplied by 1 remains the same
χ2fc−χ2f−χ2c−(−χ2)
Solution
χ2fc−χ2f−χ2c+χ2
Show Solution
