Question
Evaluate the derivative
4x34xe2xln(x)×x+2e2xx−3e2xln(x)×x
Evaluate
dxd(2x1×exln(x)×xex)
Multiply the terms
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Multiply the terms
2x1×exln(x)×xex
Multiply the terms
2xex×ln(x)×xex
Multiply the terms
2xexln(x)×xex
Multiply the terms
2x×xexln(x)×ex
Multiply the terms
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Evaluate
ex×ex
Multiply the terms with the same base by adding their exponents
ex+x
Calculate
e2x
2x×xe2xln(x)
dxd(2x×xe2xln(x))
Use differentiation rule dxd(g(x)f(x))=(g(x))2dxd(f(x))×g(x)−f(x)×dxd(g(x))
(2x×x)2dxd(e2xln(x))×2x×x−e2xln(x)×dxd(2x×x)
Calculate
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Evaluate
dxd(e2xln(x))
Use differentiation rule dxd(f(x)×g(x))=dxd(f(x))×g(x)+f(x)×dxd(g(x))
dxd(e2x)×ln(x)+e2x×dxd(ln(x))
Calculate
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Calculate
dxd(e2x)
Use the chain rule dxd(f(g))=dgd(f(g))×dxd(g) where the g=2x, to find the derivative
dgd(eg)×dxd(2x)
Use dxdex=ex to find derivative
eg×dxd(2x)
Calculate
eg×2
Substitute back
e2x×2
Multiply the terms
2e2x
2e2xln(x)+e2x×dxd(ln(x))
Use dxdlnx=x1 to find derivative
2e2xln(x)+e2x×x1
Calculate
2e2xln(x)+xe2x
Reduce fractions to a common denominator
x2e2xln(x)×x+xe2x
Write all numerators above the common denominator
x2e2xln(x)×x+e2x
(2x×x)2x2e2xln(x)×x+e2x×2x×x−e2xln(x)×dxd(2x×x)
Calculate
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Evaluate
dxd(2x×x)
Use differentiation rule dxd(f(x)×g(x))=dxd(f(x))×g(x)+f(x)×dxd(g(x))
dxd(2)×x×x+2×dxd(x)×x+2x×dxd(x)
Use dxd(c)=0 to find derivative
0×x×x+2×dxd(x)×x+2x×dxd(x)
Calculate
0+2×dxd(x)×x+2x×dxd(x)
Calculate
0+2×2x1×x+2x×dxd(x)
Calculate
0+x21+2x×dxd(x)
Use dxdxn=nxn−1 to find derivative
0+x21+2x×1
Calculate
0+x21+2x
Removing 0 doesn't change the value,so remove it from the expression
x21+2x
Use anm=nam to transform the expression
x+2x
Calculate
3x
(2x×x)2x2e2xln(x)×x+e2x×2x×x−e2xln(x)×3x
Multiply the terms
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Multiply the terms
x2e2xln(x)×x+e2x×2x×x
Cancel out the common factor x
(2e2xln(x)×x+e2x)×2x
Use the the distributive property to expand the expression
2e2xln(x)×x×2x+e2x×2x
Multiply the terms
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Evaluate
2e2xln(x)×x×2x
Multiply the terms
4e2xln(x)×xx
Use the commutative property to reorder the terms
4xe2xln(x)×x
4xe2xln(x)×x+e2x×2x
Use the commutative property to reorder the terms
4xe2xln(x)×x+2e2xx
(2x×x)24xe2xln(x)×x+2e2xx−e2xln(x)×3x
Use the commutative property to reorder the terms
(2x×x)24xe2xln(x)×x+2e2xx−3e2xln(x)×x
Solution
More Steps

Evaluate
(2x×x)2
Evaluate the power
22(x)2x2
Evaluate the power
4(x)2x2
Evaluate the power
4x×x2
Multiply the terms
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Evaluate
x×x2
Use the product rule an×am=an+m to simplify the expression
x1+2
Add the numbers
x3
4x3
4x34xe2xln(x)×x+2e2xx−3e2xln(x)×x
Show Solution
