Question
Factor the expression
(d−1)(d2+d+1)(d+1)(d2−d+1)
Evaluate
d6−1
Rewrite the expression in exponential form
(d3)2−12
Use a2−b2=(a−b)(a+b) to factor the expression
(d3−1)(d3+1)
Evaluate
More Steps

Evaluate
d3−1
Rewrite the expression in exponential form
d3−13
Use a3−b3=(a−b)(a2+ab+b2) to factor the expression
(d−1)(d2+d×1+12)
Any expression multiplied by 1 remains the same
(d−1)(d2+d+12)
1 raised to any power equals to 1
(d−1)(d2+d+1)
(d−1)(d2+d+1)(d3+1)
Solution
More Steps

Evaluate
d3+1
Rewrite the expression in exponential form
d3+13
Use a3+b3=(a+b)(a2−ab+b2) to factor the expression
(d+1)(d2−d×1+12)
Any expression multiplied by 1 remains the same
(d+1)(d2−d+12)
1 raised to any power equals to 1
(d+1)(d2−d+1)
(d−1)(d2+d+1)(d+1)(d2−d+1)
Show Solution

Find the roots
d1=−1,d2=1
Evaluate
d6−1
To find the roots of the expression,set the expression equal to 0
d6−1=0
Move the constant to the right-hand side and change its sign
d6=0+1
Removing 0 doesn't change the value,so remove it from the expression
d6=1
Take the root of both sides of the equation and remember to use both positive and negative roots
d=±61
Simplify the expression
d=±1
Separate the equation into 2 possible cases
d=1d=−1
Solution
d1=−1,d2=1
Show Solution
