Solve the differential equation

Evaluate

$$dx=-du$$

$$\text{Integrate the left-hand side of the equation with respect to }x\text{ and the right-hand side of the equation with respect to }u$$

$$\int 1dx=\int -1du$$

Calculate

More Steps

Evaluate

$$\int 1dx$$

$$\text{Use the property of integral }\int kdx=kx$$

$$x$$

$$\text{Add the constant of integral }{C}_1$$

$$x+C_1,C_1\in \mathbb{R}$$

$$x+C_1=\int -1du,C_1\in \mathbb{R}$$

Calculate

More Steps

Evaluate

$$\int -1du$$

$$\text{Use the property of integral }\int kdx=kx$$

$$-u$$

$$\text{Add the constant of integral }{C}_2$$

$$-u+C_2,C_2\in \mathbb{R}$$

$$x+C_1=-u+C_2,C_1\in \mathbb{R},C_2\in \mathbb{R}$$

Solution

$$x=-u+C,C\in \mathbb{R}$$

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