Solve e^3-1280 v^2

Question

Find the roots

v_{1} = - \frac{e 5 e}{80}, v_{2} = \frac{e 5 e}{80}

Alternative Form

v_{1} \approx - 0.125267, v_{2} \approx 0.125267

Evaluate

e^{3} - 1280 v^{2}

To find the roots of the expression,set the expression equal to 0

e^{3} - 1280 v^{2} = 0

Move the constant to the right-hand side and change its sign

- 1280 v^{2} = 0 - e^{3}

Removing 0 doesn't change the value,so remove it from the expression

- 1280 v^{2} = - e^{3}

Change the signs on both sides of the equation

1280 v^{2} = e^{3}

Divide both sides

\frac{1280 v ^{2}}{1280} = \frac{e ^{3}}{1280}

Divide the numbers

v^{2} = \frac{e ^{3}}{1280}

Take the root of both sides of the equation and remember to use both positive and negative roots

v = \pm \frac{e ^{3}}{1280}

Simplify the expression

More Steps

v = \pm \frac{e 5 e}{80}

Separate the equation into 2 possible cases

v = \frac{e 5 e}{80} v = - \frac{e 5 e}{80}

Solution

v_{1} = - \frac{e 5 e}{80}, v_{2} = \frac{e 5 e}{80}

Alternative Form

v_{1} \approx - 0.125267, v_{2} \approx 0.125267

Show Solution