Solve e^5-2440 v^2

Question

Find the roots

v_{1} = - \frac{e ^{2} 610 e}{1220}, v_{2} = \frac{e ^{2} 610 e}{1220}

Alternative Form

v_{1} \approx - 0.246627, v_{2} \approx 0.246627

Evaluate

e^{5} - 2440 v^{2}

To find the roots of the expression,set the expression equal to 0

e^{5} - 2440 v^{2} = 0

Move the constant to the right-hand side and change its sign

- 2440 v^{2} = 0 - e^{5}

Removing 0 doesn't change the value,so remove it from the expression

- 2440 v^{2} = - e^{5}

Change the signs on both sides of the equation

2440 v^{2} = e^{5}

Divide both sides

\frac{2440 v ^{2}}{2440} = \frac{e ^{5}}{2440}

Divide the numbers

v^{2} = \frac{e ^{5}}{2440}

Take the root of both sides of the equation and remember to use both positive and negative roots

v = \pm \frac{e ^{5}}{2440}

Simplify the expression

More Steps

v = \pm \frac{e ^{2} 610 e}{1220}

Separate the equation into 2 possible cases

v = \frac{e ^{2} 610 e}{1220} v = - \frac{e ^{2} 610 e}{1220}

Solution

v_{1} = - \frac{e ^{2} 610 e}{1220}, v_{2} = \frac{e ^{2} 610 e}{1220}

Alternative Form

v_{1} \approx - 0.246627, v_{2} \approx 0.246627

Show Solution