Solve e^5-2640 v^2

Question

Find the roots

v_{1} = - \frac{e ^{2} 165 e}{660}, v_{2} = \frac{e ^{2} 165 e}{660}

Alternative Form

v_{1} \approx - 0.237101, v_{2} \approx 0.237101

Evaluate

e^{5} - 2640 v^{2}

To find the roots of the expression,set the expression equal to 0

e^{5} - 2640 v^{2} = 0

Move the constant to the right-hand side and change its sign

- 2640 v^{2} = 0 - e^{5}

Removing 0 doesn't change the value,so remove it from the expression

- 2640 v^{2} = - e^{5}

Change the signs on both sides of the equation

2640 v^{2} = e^{5}

Divide both sides

\frac{2640 v ^{2}}{2640} = \frac{e ^{5}}{2640}

Divide the numbers

v^{2} = \frac{e ^{5}}{2640}

Take the root of both sides of the equation and remember to use both positive and negative roots

v = \pm \frac{e ^{5}}{2640}

Simplify the expression

More Steps

v = \pm \frac{e ^{2} 165 e}{660}

Separate the equation into 2 possible cases

v = \frac{e ^{2} 165 e}{660} v = - \frac{e ^{2} 165 e}{660}

Solution

v_{1} = - \frac{e ^{2} 165 e}{660}, v_{2} = \frac{e ^{2} 165 e}{660}

Alternative Form

v_{1} \approx - 0.237101, v_{2} \approx 0.237101

Show Solution