Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve for f
f∈(−∞,−19]∪[19,+∞)
Evaluate
f×f−2−2≥15
Simplify
More Steps

Evaluate
f×f−2−2
Multiply the terms
f2−2−2
Subtract the numbers
f2−4
f2−4≥15
Move the expression to the left side
f2−4−15≥0
Subtract the numbers
f2−19≥0
Rewrite the expression
f2−19=0
Move the constant to the right-hand side and change its sign
f2=0+19
Removing 0 doesn't change the value,so remove it from the expression
f2=19
Take the root of both sides of the equation and remember to use both positive and negative roots
f=±19
Separate the equation into 2 possible cases
f=19f=−19
Determine the test intervals using the critical values
f<−19−19<f<19f>19
Choose a value form each interval
f1=−5f2=0f3=5
To determine if f<−19 is the solution to the inequality,test if the chosen value f=−5 satisfies the initial inequality
More Steps

Evaluate
(−5)2−4≥15
Subtract the numbers
More Steps

Evaluate
(−5)2−4
Simplify
52−4
Evaluate the power
25−4
Subtract the numbers
21
21≥15
Check the inequality
true
f<−19 is the solutionf2=0f3=5
To determine if −19<f<19 is the solution to the inequality,test if the chosen value f=0 satisfies the initial inequality
More Steps

Evaluate
02−4≥15
Simplify
More Steps

Evaluate
02−4
Calculate
0−4
Removing 0 doesn't change the value,so remove it from the expression
−4
−4≥15
Check the inequality
false
f<−19 is the solution−19<f<19 is not a solutionf3=5
To determine if f>19 is the solution to the inequality,test if the chosen value f=5 satisfies the initial inequality
More Steps

Evaluate
52−4≥15
Subtract the numbers
More Steps

Evaluate
52−4
Evaluate the power
25−4
Subtract the numbers
21
21≥15
Check the inequality
true
f<−19 is the solution−19<f<19 is not a solutionf>19 is the solution
The original inequality is a nonstrict inequality,so include the critical value in the solution
f≤−19 is the solutionf≥19 is the solution
Solution
f∈(−∞,−19]∪[19,+∞)
Show Solution
