Solve f-16 f^35 - ScanMath

Question

Simplify the expression

f - 80 f^{3}

Evaluate

f - 16 f^{3} \times 5

Solution

f - 80 f^{3}

Show Solution

f (1 - 80 f^{2})

Evaluate

f - 16 f^{3} \times 5

Multiply the terms

f - 80 f^{3}

Rewrite the expression

f - f \times 80 f^{2}

Solution

f (1 - 80 f^{2})

Show Solution

f_{1} = - \frac{5}{20}, f_{2} = 0, f_{3} = \frac{5}{20}

Alternative Form

f_{1} \approx - 0.111803, f_{2} = 0, f_{3} \approx 0.111803

Evaluate

f - 16 f^{3} \times 5

To find the roots of the expression,set the expression equal to 0

f - 16 f^{3} \times 5 = 0

Multiply the terms

f - 80 f^{3} = 0

Factor the expression

f (1 - 80 f^{2}) = 0

Separate the equation into 2 possible cases

f = 0 1 - 80 f^{2} = 0

Solve the equation

More Steps

Evaluate

1 - 80 f^{2} = 0

Move the constant to the right-hand side and change its sign

- 80 f^{2} = 0 - 1

Removing 0 doesn't change the value,so remove it from the expression

- 80 f^{2} = - 1

Change the signs on both sides of the equation

80 f^{2} = 1

Divide both sides

\frac{80 f ^{2}}{80} = \frac{1}{80}

Divide the numbers

f^{2} = \frac{1}{80}

Take the root of both sides of the equation and remember to use both positive and negative roots

f = \pm \frac{1}{80}

Simplify the expression

More Steps

Evaluate

\frac{1}{80}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{1}{80}

Simplify the radical expression

\frac{1}{80}

Simplify the radical expression

\frac{1}{4 5}

Multiply by the Conjugate

\frac{5}{4 5 \times 5}

Multiply the numbers

\frac{5}{20}

f = \pm \frac{5}{20}

Separate the equation into 2 possible cases

f = \frac{5}{20} f = - \frac{5}{20}

f = 0 f = \frac{5}{20} f = - \frac{5}{20}

Solution

f_{1} = - \frac{5}{20}, f_{2} = 0, f_{3} = \frac{5}{20}

Alternative Form

f_{1} \approx - 0.111803, f_{2} = 0, f_{3} \approx 0.111803

Show Solution