Solve g^240-16 - ScanMath

Question

Simplify the expression

40 g^{2} - 16

Evaluate

g^{2} \times 40 - 16

Solution

40 g^{2} - 16

Show Solution

8 (5 g^{2} - 2)

Evaluate

g^{2} \times 40 - 16

Use the commutative property to reorder the terms

40 g^{2} - 16

Solution

8 (5 g^{2} - 2)

Show Solution

g_{1} = - \frac{10}{5}, g_{2} = \frac{10}{5}

Alternative Form

g_{1} \approx - 0.632456, g_{2} \approx 0.632456

Evaluate

g^{2} \times 40 - 16

To find the roots of the expression,set the expression equal to 0

g^{2} \times 40 - 16 = 0

Use the commutative property to reorder the terms

40 g^{2} - 16 = 0

Move the constant to the right-hand side and change its sign

40 g^{2} = 0 + 16

Removing 0 doesn't change the value,so remove it from the expression

40 g^{2} = 16

Divide both sides

\frac{40 g ^{2}}{40} = \frac{16}{40}

Divide the numbers

g^{2} = \frac{16}{40}

Cancel out the common factor 8

g^{2} = \frac{2}{5}

Take the root of both sides of the equation and remember to use both positive and negative roots

g = \pm \frac{2}{5}

Simplify the expression

More Steps

Evaluate

\frac{2}{5}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{2}{5}

Multiply by the Conjugate

\frac{2 \times 5}{5 \times 5}

Multiply the numbers

More Steps

Evaluate

2 \times 5

The product of roots with the same index is equal to the root of the product

2 \times 5

Calculate the product

10

\frac{10}{5 \times 5}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{10}{5}

g = \pm \frac{10}{5}

Separate the equation into 2 possible cases

g = \frac{10}{5} g = - \frac{10}{5}

Solution

g_{1} = - \frac{10}{5}, g_{2} = \frac{10}{5}

Alternative Form

g_{1} \approx - 0.632456, g_{2} \approx 0.632456

Show Solution