Question
Factor the expression
h2(1−h)(1+h)(1+h2)
Evaluate
h2−h6
Factor out h2 from the expression
h2(1−h4)
Factor the expression
More Steps

Evaluate
1−h4
Rewrite the expression in exponential form
12−(h2)2
Use a2−b2=(a−b)(a+b) to factor the expression
(1−h2)(1+h2)
h2(1−h2)(1+h2)
Solution
More Steps

Evaluate
1−h2
Rewrite the expression in exponential form
12−h2
Use a2−b2=(a−b)(a+b) to factor the expression
(1−h)(1+h)
h2(1−h)(1+h)(1+h2)
Show Solution

Find the roots
h1=−1,h2=0,h3=1
Evaluate
h2−h6
To find the roots of the expression,set the expression equal to 0
h2−h6=0
Factor the expression
h2(1−h4)=0
Separate the equation into 2 possible cases
h2=01−h4=0
The only way a power can be 0 is when the base equals 0
h=01−h4=0
Solve the equation
More Steps

Evaluate
1−h4=0
Move the constant to the right-hand side and change its sign
−h4=0−1
Removing 0 doesn't change the value,so remove it from the expression
−h4=−1
Change the signs on both sides of the equation
h4=1
Take the root of both sides of the equation and remember to use both positive and negative roots
h=±41
Simplify the expression
h=±1
Separate the equation into 2 possible cases
h=1h=−1
h=0h=1h=−1
Solution
h1=−1,h2=0,h3=1
Show Solution
