Solve h^3815-39-0

Question

Simplify the expression

815 h^{3} - 39

Evaluate

h^{3} \times 815 - 39 - 0

Use the commutative property to reorder the terms

815 h^{3} - 39 - 0

Solution

815 h^{3} - 39

Show Solution

h = \frac{3 39 \times 81 5 ^{2}}{815}

Alternative Form

h \approx 0.363052

Evaluate

h^{3} \times 815 - 39 - 0

To find the roots of the expression,set the expression equal to 0

h^{3} \times 815 - 39 - 0 = 0

Use the commutative property to reorder the terms

815 h^{3} - 39 - 0 = 0

Removing 0 doesn't change the value,so remove it from the expression

815 h^{3} - 39 = 0

Move the constant to the right-hand side and change its sign

815 h^{3} = 0 + 39

Removing 0 doesn't change the value,so remove it from the expression

815 h^{3} = 39

Divide both sides

\frac{815 h ^{3}}{815} = \frac{39}{815}

Divide the numbers

h^{3} = \frac{39}{815}

Take the 3 -th root on both sides of the equation

3 h^{3} = 3 \frac{39}{815}

Calculate

h = 3 \frac{39}{815}

Solution

More Steps

Evaluate

3 \frac{39}{815}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{3 39}{3 815}

Multiply by the Conjugate

\frac{3 39 \times 3 81 5 ^{2}}{3 815 \times 3 81 5 ^{2}}

The product of roots with the same index is equal to the root of the product

\frac{3 39 \times 81 5 ^{2}}{3 815 \times 3 81 5 ^{2}}

Multiply the numbers

More Steps

Evaluate

3815 \times 3 81 5^{2}

The product of roots with the same index is equal to the root of the product

3 815 \times 81 5^{2}

Calculate the product

3 81 5^{3}

Reduce the index of the radical and exponent with 3

815

\frac{3 39 \times 81 5 ^{2}}{815}

h = \frac{3 39 \times 81 5 ^{2}}{815}

Alternative Form

h \approx 0.363052

Show Solution