Solve h^4141-23-0

Question

Simplify the expression

141 h^{4} - 23

Evaluate

h^{4} \times 141 - 23 - 0

Use the commutative property to reorder the terms

141 h^{4} - 23 - 0

Solution

141 h^{4} - 23

Show Solution

h_{1} = - \frac{4 23 \times 14 1 ^{3}}{141}, h_{2} = \frac{4 23 \times 14 1 ^{3}}{141}

Alternative Form

h_{1} \approx - 0.635517, h_{2} \approx 0.635517

Evaluate

h^{4} \times 141 - 23 - 0

To find the roots of the expression,set the expression equal to 0

h^{4} \times 141 - 23 - 0 = 0

Use the commutative property to reorder the terms

141 h^{4} - 23 - 0 = 0

Removing 0 doesn't change the value,so remove it from the expression

141 h^{4} - 23 = 0

Move the constant to the right-hand side and change its sign

141 h^{4} = 0 + 23

Removing 0 doesn't change the value,so remove it from the expression

141 h^{4} = 23

Divide both sides

\frac{141 h ^{4}}{141} = \frac{23}{141}

Divide the numbers

h^{4} = \frac{23}{141}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm 4 \frac{23}{141}

Simplify the expression

More Steps

Evaluate

4 \frac{23}{141}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 23}{4 141}

Multiply by the Conjugate

\frac{4 23 \times 4 14 1 ^{3}}{4 141 \times 4 14 1 ^{3}}

The product of roots with the same index is equal to the root of the product

\frac{4 23 \times 14 1 ^{3}}{4 141 \times 4 14 1 ^{3}}

Multiply the numbers

More Steps

Evaluate

4141 \times 4 14 1^{3}

The product of roots with the same index is equal to the root of the product

4 141 \times 14 1^{3}

Calculate the product

4 14 1^{4}

Reduce the index of the radical and exponent with 4

141

\frac{4 23 \times 14 1 ^{3}}{141}

h = \pm \frac{4 23 \times 14 1 ^{3}}{141}

Separate the equation into 2 possible cases

h = \frac{4 23 \times 14 1 ^{3}}{141} h = - \frac{4 23 \times 14 1 ^{3}}{141}

Solution

h_{1} = - \frac{4 23 \times 14 1 ^{3}}{141}, h_{2} = \frac{4 23 \times 14 1 ^{3}}{141}

Alternative Form

h_{1} \approx - 0.635517, h_{2} \approx 0.635517

Show Solution