Solve h^4161-2-0 - ScanMath

Question

Simplify the expression

161 h^{4} - 2

Evaluate

h^{4} \times 161 - 2 - 0

Use the commutative property to reorder the terms

161 h^{4} - 2 - 0

Solution

161 h^{4} - 2

Show Solution

h_{1} = - \frac{4 2 \times 16 1 ^{3}}{161}, h_{2} = \frac{4 2 \times 16 1 ^{3}}{161}

Alternative Form

h_{1} \approx - 0.33385, h_{2} \approx 0.33385

Evaluate

h^{4} \times 161 - 2 - 0

To find the roots of the expression,set the expression equal to 0

h^{4} \times 161 - 2 - 0 = 0

Use the commutative property to reorder the terms

161 h^{4} - 2 - 0 = 0

Removing 0 doesn't change the value,so remove it from the expression

161 h^{4} - 2 = 0

Move the constant to the right-hand side and change its sign

161 h^{4} = 0 + 2

Removing 0 doesn't change the value,so remove it from the expression

161 h^{4} = 2

Divide both sides

\frac{161 h ^{4}}{161} = \frac{2}{161}

Divide the numbers

h^{4} = \frac{2}{161}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm 4 \frac{2}{161}

Simplify the expression

More Steps

Evaluate

4 \frac{2}{161}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 2}{4 161}

Multiply by the Conjugate

\frac{4 2 \times 4 16 1 ^{3}}{4 161 \times 4 16 1 ^{3}}

The product of roots with the same index is equal to the root of the product

\frac{4 2 \times 16 1 ^{3}}{4 161 \times 4 16 1 ^{3}}

Multiply the numbers

More Steps

Evaluate

4161 \times 4 16 1^{3}

The product of roots with the same index is equal to the root of the product

4 161 \times 16 1^{3}

Calculate the product

4 16 1^{4}

Reduce the index of the radical and exponent with 4

161

\frac{4 2 \times 16 1 ^{3}}{161}

h = \pm \frac{4 2 \times 16 1 ^{3}}{161}

Separate the equation into 2 possible cases

h = \frac{4 2 \times 16 1 ^{3}}{161} h = - \frac{4 2 \times 16 1 ^{3}}{161}

Solution

h_{1} = - \frac{4 2 \times 16 1 ^{3}}{161}, h_{2} = \frac{4 2 \times 16 1 ^{3}}{161}

Alternative Form

h_{1} \approx - 0.33385, h_{2} \approx 0.33385

Show Solution