Solve h^4527-3-0 - ScanMath

Question

Simplify the expression

527 h^{4} - 3

Evaluate

h^{4} \times 527 - 3 - 0

Use the commutative property to reorder the terms

527 h^{4} - 3 - 0

Solution

527 h^{4} - 3

Show Solution

h_{1} = - \frac{4 3 \times 52 7 ^{3}}{527}, h_{2} = \frac{4 3 \times 52 7 ^{3}}{527}

Alternative Form

h_{1} \approx - 0.27468, h_{2} \approx 0.27468

Evaluate

h^{4} \times 527 - 3 - 0

To find the roots of the expression,set the expression equal to 0

h^{4} \times 527 - 3 - 0 = 0

Use the commutative property to reorder the terms

527 h^{4} - 3 - 0 = 0

Removing 0 doesn't change the value,so remove it from the expression

527 h^{4} - 3 = 0

Move the constant to the right-hand side and change its sign

527 h^{4} = 0 + 3

Removing 0 doesn't change the value,so remove it from the expression

527 h^{4} = 3

Divide both sides

\frac{527 h ^{4}}{527} = \frac{3}{527}

Divide the numbers

h^{4} = \frac{3}{527}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm 4 \frac{3}{527}

Simplify the expression

More Steps

Evaluate

4 \frac{3}{527}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 3}{4 527}

Multiply by the Conjugate

\frac{4 3 \times 4 52 7 ^{3}}{4 527 \times 4 52 7 ^{3}}

The product of roots with the same index is equal to the root of the product

\frac{4 3 \times 52 7 ^{3}}{4 527 \times 4 52 7 ^{3}}

Multiply the numbers

More Steps

Evaluate

4527 \times 4 52 7^{3}

The product of roots with the same index is equal to the root of the product

4 527 \times 52 7^{3}

Calculate the product

4 52 7^{4}

Reduce the index of the radical and exponent with 4

527

\frac{4 3 \times 52 7 ^{3}}{527}

h = \pm \frac{4 3 \times 52 7 ^{3}}{527}

Separate the equation into 2 possible cases

h = \frac{4 3 \times 52 7 ^{3}}{527} h = - \frac{4 3 \times 52 7 ^{3}}{527}

Solution

h_{1} = - \frac{4 3 \times 52 7 ^{3}}{527}, h_{2} = \frac{4 3 \times 52 7 ^{3}}{527}

Alternative Form

h_{1} \approx - 0.27468, h_{2} \approx 0.27468

Show Solution