Solve h^4604-17-0

Question

Simplify the expression

604 h^{4} - 17

Evaluate

h^{4} \times 604 - 17 - 0

Use the commutative property to reorder the terms

604 h^{4} - 17 - 0

Solution

604 h^{4} - 17

Show Solution

h_{1} = - \frac{4 17 \times 60 4 ^{3}}{604}, h_{2} = \frac{4 17 \times 60 4 ^{3}}{604}

Alternative Form

h_{1} \approx - 0.409593, h_{2} \approx 0.409593

Evaluate

h^{4} \times 604 - 17 - 0

To find the roots of the expression,set the expression equal to 0

h^{4} \times 604 - 17 - 0 = 0

Use the commutative property to reorder the terms

604 h^{4} - 17 - 0 = 0

Removing 0 doesn't change the value,so remove it from the expression

604 h^{4} - 17 = 0

Move the constant to the right-hand side and change its sign

604 h^{4} = 0 + 17

Removing 0 doesn't change the value,so remove it from the expression

604 h^{4} = 17

Divide both sides

\frac{604 h ^{4}}{604} = \frac{17}{604}

Divide the numbers

h^{4} = \frac{17}{604}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm 4 \frac{17}{604}

Simplify the expression

More Steps

Evaluate

4 \frac{17}{604}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 17}{4 604}

Multiply by the Conjugate

\frac{4 17 \times 4 60 4 ^{3}}{4 604 \times 4 60 4 ^{3}}

The product of roots with the same index is equal to the root of the product

\frac{4 17 \times 60 4 ^{3}}{4 604 \times 4 60 4 ^{3}}

Multiply the numbers

More Steps

Evaluate

4604 \times 4 60 4^{3}

The product of roots with the same index is equal to the root of the product

4 604 \times 60 4^{3}

Calculate the product

4 60 4^{4}

Reduce the index of the radical and exponent with 4

604

\frac{4 17 \times 60 4 ^{3}}{604}

h = \pm \frac{4 17 \times 60 4 ^{3}}{604}

Separate the equation into 2 possible cases

h = \frac{4 17 \times 60 4 ^{3}}{604} h = - \frac{4 17 \times 60 4 ^{3}}{604}

Solution

h_{1} = - \frac{4 17 \times 60 4 ^{3}}{604}, h_{2} = \frac{4 17 \times 60 4 ^{3}}{604}

Alternative Form

h_{1} \approx - 0.409593, h_{2} \approx 0.409593

Show Solution