Solve h^5253-41-0

Question

Simplify the expression

253 h^{5} - 41

Evaluate

h^{5} \times 253 - 41 - 0

Use the commutative property to reorder the terms

253 h^{5} - 41 - 0

Solution

253 h^{5} - 41

Show Solution

h = \frac{5 41 \times 25 3 ^{4}}{253}

Alternative Form

h \approx 0.694917

Evaluate

h^{5} \times 253 - 41 - 0

To find the roots of the expression,set the expression equal to 0

h^{5} \times 253 - 41 - 0 = 0

Use the commutative property to reorder the terms

253 h^{5} - 41 - 0 = 0

Removing 0 doesn't change the value,so remove it from the expression

253 h^{5} - 41 = 0

Move the constant to the right-hand side and change its sign

253 h^{5} = 0 + 41

Removing 0 doesn't change the value,so remove it from the expression

253 h^{5} = 41

Divide both sides

\frac{253 h ^{5}}{253} = \frac{41}{253}

Divide the numbers

h^{5} = \frac{41}{253}

Take the 5 -th root on both sides of the equation

5 h^{5} = 5 \frac{41}{253}

Calculate

h = 5 \frac{41}{253}

Solution

More Steps

Evaluate

5 \frac{41}{253}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{5 41}{5 253}

Multiply by the Conjugate

\frac{5 41 \times 5 25 3 ^{4}}{5 253 \times 5 25 3 ^{4}}

The product of roots with the same index is equal to the root of the product

\frac{5 41 \times 25 3 ^{4}}{5 253 \times 5 25 3 ^{4}}

Multiply the numbers

More Steps

Evaluate

5253 \times 5 25 3^{4}

The product of roots with the same index is equal to the root of the product

5 253 \times 25 3^{4}

Calculate the product

5 25 3^{5}

Reduce the index of the radical and exponent with 5

253

\frac{5 41 \times 25 3 ^{4}}{253}

h = \frac{5 41 \times 25 3 ^{4}}{253}

Alternative Form

h \approx 0.694917

Show Solution