Solve h^6502-4 - ScanMath

Question

Simplify the expression

502 h^{6} - 4

Evaluate

h^{6} \times 502 - 4

Solution

502 h^{6} - 4

Show Solution

2 (251 h^{6} - 2)

Evaluate

h^{6} \times 502 - 4

Use the commutative property to reorder the terms

502 h^{6} - 4

Solution

2 (251 h^{6} - 2)

Show Solution

h_{1} = - \frac{6 2 \times 25 1 ^{5}}{251}, h_{2} = \frac{6 2 \times 25 1 ^{5}}{251}

Alternative Form

h_{1} \approx - 0.446916, h_{2} \approx 0.446916

Evaluate

h^{6} \times 502 - 4

To find the roots of the expression,set the expression equal to 0

h^{6} \times 502 - 4 = 0

Use the commutative property to reorder the terms

502 h^{6} - 4 = 0

Move the constant to the right-hand side and change its sign

502 h^{6} = 0 + 4

Removing 0 doesn't change the value,so remove it from the expression

502 h^{6} = 4

Divide both sides

\frac{502 h ^{6}}{502} = \frac{4}{502}

Divide the numbers

h^{6} = \frac{4}{502}

Cancel out the common factor 2

h^{6} = \frac{2}{251}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm 6 \frac{2}{251}

Simplify the expression

More Steps

Evaluate

6 \frac{2}{251}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{6 2}{6 251}

Multiply by the Conjugate

\frac{6 2 \times 6 25 1 ^{5}}{6 251 \times 6 25 1 ^{5}}

The product of roots with the same index is equal to the root of the product

\frac{6 2 \times 25 1 ^{5}}{6 251 \times 6 25 1 ^{5}}

Multiply the numbers

More Steps

Evaluate

6251 \times 6 25 1^{5}

The product of roots with the same index is equal to the root of the product

6 251 \times 25 1^{5}

Calculate the product

6 25 1^{6}

Reduce the index of the radical and exponent with 6

251

\frac{6 2 \times 25 1 ^{5}}{251}

h = \pm \frac{6 2 \times 25 1 ^{5}}{251}

Separate the equation into 2 possible cases

h = \frac{6 2 \times 25 1 ^{5}}{251} h = - \frac{6 2 \times 25 1 ^{5}}{251}

Solution

h_{1} = - \frac{6 2 \times 25 1 ^{5}}{251}, h_{2} = \frac{6 2 \times 25 1 ^{5}}{251}

Alternative Form

h_{1} \approx - 0.446916, h_{2} \approx 0.446916

Show Solution