Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve for h
−62<h<62
Alternative Form
h∈(−62,62)
Evaluate
h×h5−1<1
Multiply the terms
More Steps

Evaluate
h×h5
Use the product rule an×am=an+m to simplify the expression
h1+5
Add the numbers
h6
h6−1<1
Move the expression to the left side
h6−1−1<0
Subtract the numbers
h6−2<0
Rewrite the expression
h6−2=0
Move the constant to the right-hand side and change its sign
h6=0+2
Removing 0 doesn't change the value,so remove it from the expression
h6=2
Take the root of both sides of the equation and remember to use both positive and negative roots
h=±62
Separate the equation into 2 possible cases
h=62h=−62
Determine the test intervals using the critical values
h<−62−62<h<62h>62
Choose a value form each interval
h1=−2h2=0h3=2
To determine if h<−62 is the solution to the inequality,test if the chosen value h=−2 satisfies the initial inequality
More Steps

Evaluate
(−2)6−1<1
Subtract the numbers
More Steps

Evaluate
(−2)6−1
Simplify
26−1
Evaluate the power
64−1
Subtract the numbers
63
63<1
Check the inequality
false
h<−62 is not a solutionh2=0h3=2
To determine if −62<h<62 is the solution to the inequality,test if the chosen value h=0 satisfies the initial inequality
More Steps

Evaluate
06−1<1
Simplify
More Steps

Evaluate
06−1
Calculate
0−1
Removing 0 doesn't change the value,so remove it from the expression
−1
−1<1
Check the inequality
true
h<−62 is not a solution−62<h<62 is the solutionh3=2
To determine if h>62 is the solution to the inequality,test if the chosen value h=2 satisfies the initial inequality
More Steps

Evaluate
26−1<1
Subtract the numbers
More Steps

Evaluate
26−1
Evaluate the power
64−1
Subtract the numbers
63
63<1
Check the inequality
false
h<−62 is not a solution−62<h<62 is the solutionh>62 is not a solution
Solution
−62<h<62
Alternative Form
h∈(−62,62)
Show Solution
