Question Evaluate the integral 235h2+C,C∈R Evaluate ∫35hdhUse the property of integral ∫kf(x)dx=k∫f(x)dx 35×∫hdhUse the property of integral ∫xndx=n+1xn+1 35×1+1h1+1Simplify More Steps Evaluate 1+1h1+1Add the numbers 1+1h2Add the numbers 2h2 35×2h2Multiply the terms 235h2Solution 235h2+C,C∈R Show Solution