Question Evaluate the integral 2n2+C,C∈R Evaluate ∫4ndnUse the property of integral ∫kf(x)dx=k∫f(x)dx 4×∫ndnUse the property of integral ∫xndx=n+1xn+1 4×1+1n1+1Simplify More Steps Evaluate 1+1n1+1Add the numbers 1+1n2Add the numbers 2n2 4×2n2Cancel out the common factor 2 2n2Solution 2n2+C,C∈R Show Solution