Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
j1=5−38,j2=5+38
Alternative Form
j1≈−1.164414,j2≈11.164414
Evaluate
j2−10j=13
Move the expression to the left side
j2−10j−13=0
Substitute a=1,b=−10 and c=−13 into the quadratic formula j=2a−b±b2−4ac
j=210±(−10)2−4(−13)
Simplify the expression
More Steps

Evaluate
(−10)2−4(−13)
Multiply the numbers
More Steps

Evaluate
4(−13)
Multiplying or dividing an odd number of negative terms equals a negative
−4×13
Multiply the numbers
−52
(−10)2−(−52)
Rewrite the expression
102−(−52)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
102+52
Evaluate the power
100+52
Add the numbers
152
j=210±152
Simplify the radical expression
More Steps

Evaluate
152
Write the expression as a product where the root of one of the factors can be evaluated
4×38
Write the number in exponential form with the base of 2
22×38
The root of a product is equal to the product of the roots of each factor
22×38
Reduce the index of the radical and exponent with 2
238
j=210±238
Separate the equation into 2 possible cases
j=210+238j=210−238
Simplify the expression
More Steps

Evaluate
j=210+238
Divide the terms
More Steps

Evaluate
210+238
Rewrite the expression
22(5+38)
Reduce the fraction
5+38
j=5+38
j=5+38j=210−238
Simplify the expression
More Steps

Evaluate
j=210−238
Divide the terms
More Steps

Evaluate
210−238
Rewrite the expression
22(5−38)
Reduce the fraction
5−38
j=5−38
j=5+38j=5−38
Solution
j1=5−38,j2=5+38
Alternative Form
j1≈−1.164414,j2≈11.164414
Show Solution
