Solve k^202-2002-126

Question

Simplify the expression

2 k^{2} - 2128

Evaluate

k^{2} \times 2 - 2002 - 126

Use the commutative property to reorder the terms

2 k^{2} - 2002 - 126

Solution

2 k^{2} - 2128

Show Solution

2 (k^{2} - 1064)

Evaluate

k^{2} \times 2 - 2002 - 126

Use the commutative property to reorder the terms

2 k^{2} - 2002 - 126

Subtract the numbers

2 k^{2} - 2128

Solution

2 (k^{2} - 1064)

Show Solution

k_{1} = - 2266, k_{2} = 2266

Alternative Form

k_{1} \approx - 32.619013, k_{2} \approx 32.619013

Evaluate

k^{2} \times 2 - 2002 - 126

To find the roots of the expression,set the expression equal to 0

k^{2} \times 2 - 2002 - 126 = 0

Use the commutative property to reorder the terms

2 k^{2} - 2002 - 126 = 0

Subtract the numbers

2 k^{2} - 2128 = 0

Move the constant to the right-hand side and change its sign

2 k^{2} = 0 + 2128

Removing 0 doesn't change the value,so remove it from the expression

2 k^{2} = 2128

Divide both sides

\frac{2 k ^{2}}{2} = \frac{2128}{2}

Divide the numbers

k^{2} = \frac{2128}{2}

Divide the numbers

More Steps

Evaluate

\frac{2128}{2}

Reduce the numbers

\frac{1064}{1}

Calculate

1064

k^{2} = 1064

Take the root of both sides of the equation and remember to use both positive and negative roots

k = \pm 1064

Simplify the expression

More Steps

Evaluate

1064

Write the expression as a product where the root of one of the factors can be evaluated

4 \times 266

Write the number in exponential form with the base of 2

2^{2} \times 266

The root of a product is equal to the product of the roots of each factor

2^{2} \times 266

Reduce the index of the radical and exponent with 2

2266

k = \pm 2266

Separate the equation into 2 possible cases

k = 2266 k = - 2266

Solution

k_{1} = - 2266, k_{2} = 2266

Alternative Form

k_{1} \approx - 32.619013, k_{2} \approx 32.619013

Show Solution