Solve k^415 110/70-12

Question

Simplify the expression

\frac{116}{7} k^{4} - 12

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\frac{4}{7} (29 k^{4} - 21)

Show Solution

k_{1} = - \frac{4 512169}{29}, k_{2} = \frac{4 512169}{29}

Alternative Form

k_{1} \approx - 0.922477, k_{2} \approx 0.922477

Evaluate

k^{4} \times 15 \frac{110}{70} - 12

To find the roots of the expression,set the expression equal to 0

k^{4} \times 15 \frac{110}{70} - 12 = 0

Covert the mixed number to an improper fraction

More Steps

k^{4} \times \frac{1160}{70} - 12 = 0

Use the commutative property to reorder the terms

More Steps

\frac{116}{7} k^{4} - 12 = 0

Move the constant to the right-hand side and change its sign

\frac{116}{7} k^{4} = 0 + 12

Removing 0 doesn't change the value,so remove it from the expression

\frac{116}{7} k^{4} = 12

Multiply by the reciprocal

\frac{116}{7} k^{4} \times \frac{7}{116} = 12 \times \frac{7}{116}

Multiply

k^{4} = 12 \times \frac{7}{116}

Multiply

More Steps

k^{4} = \frac{21}{29}

Take the root of both sides of the equation and remember to use both positive and negative roots

k = \pm 4 \frac{21}{29}

Simplify the expression

More Steps

k = \pm \frac{4 512169}{29}

Separate the equation into 2 possible cases

k = \frac{4 512169}{29} k = - \frac{4 512169}{29}

Solution

k_{1} = - \frac{4 512169}{29}, k_{2} = \frac{4 512169}{29}

Alternative Form

k_{1} \approx - 0.922477, k_{2} \approx 0.922477

Show Solution