Solve l^53828-1 - ScanMath

Evaluate

l^{5} \times 3828 - 1

To find the roots of the expression,set the expression equal to 0

l^{5} \times 3828 - 1 = 0

Use the commutative property to reorder the terms

3828 l^{5} - 1 = 0

Move the constant to the right-hand side and change its sign

3828 l^{5} = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

3828 l^{5} = 1

Divide both sides

\frac{3828 l ^{5}}{3828} = \frac{1}{3828}

Divide the numbers

l^{5} = \frac{1}{3828}

Take the 5 -th root on both sides of the equation

5 l^{5} = 5 \frac{1}{3828}

Calculate

l = 5 \frac{1}{3828}

Solution

More Steps

l = \frac{5 382 8 ^{4}}{3828}

Alternative Form

l \approx 0.192046

Simplify the expression